A must read for all cricket lovers with science background :-).
A good article from Joe Wolfe (School of Physics, University of New South Wales)
The diagram at below shows how a batsman leaves a parallel slit (width a = 180 mm) between bat and pad, through which a cricket ball with momentum p can diffract. On 23 October, 1999, Australian captain Steve ('Tugga') Waugh, perhaps because of his intuitive knowledge of quantum mechanics, appears to have set the field at maxima in |Y2|, where Y is the wave function of the cricket ball, as is shown in the photograph below. Showing all reasoning and calculation, determine
Just in case: Newtonian mechanics (including the fluid mechanics of the air) is completely adequate to describe the behaviour of cricket balls, although the existence, stability and chemical properties of the atoms and molecules of which they are made are all determined by quantum mechanics. So yes, the whole page above is a joke, whose original purpose was both to amuse first year physics students and to demonstrate the very small size of quantum mechanical effects in the familiar, macroscopic world. The Brownian motion of the cricket ball (its irregular, random motion due to its collisions with molecules of air) is typically ten billion times greater than the velocity calculated above. The disturbance of quantum mechanical effects such as particle interference by random thermal motion is why even nano-scale quantum effects are often studied at low temperatures.
A good article from Joe Wolfe (School of Physics, University of New South Wales)
The diagram at below shows how a batsman leaves a parallel slit (width a = 180 mm) between bat and pad, through which a cricket ball with momentum p can diffract. On 23 October, 1999, Australian captain Steve ('Tugga') Waugh, perhaps because of his intuitive knowledge of quantum mechanics, appears to have set the field at maxima in |Y2|, where Y is the wave function of the cricket ball, as is shown in the photograph below. Showing all reasoning and calculation, determine
- 1) whom he should ask to bowl, and
2) howzat?
We also answer one classical question about cricket ball motion.
The small angle approximation is a bit crude for the angular spacing Dq, but will suffice for this approximate analysis, so
- Dq ~ l.Da/pa,
- Dq ~ l/a,
- Dq ~ h/amv, so:
v ~ h/amDq = hL/amDy
We return now to question (2) about the fate of the batsman. Is he
- a) out caught
b) out lbw
c) out interfering with ball?
For cricket lovers: the bowler was Damien Flemming. The batsman was David Mutandera of Zimbabwe. This is believed to be the first time in cricket history such a field has been employed in an international one day match. Zimbabwe were all out for 116 runs in the second one day international at the Harare Sports Club, 23 October 1999.
Just in case: Newtonian mechanics (including the fluid mechanics of the air) is completely adequate to describe the behaviour of cricket balls, although the existence, stability and chemical properties of the atoms and molecules of which they are made are all determined by quantum mechanics. So yes, the whole page above is a joke, whose original purpose was both to amuse first year physics students and to demonstrate the very small size of quantum mechanical effects in the familiar, macroscopic world. The Brownian motion of the cricket ball (its irregular, random motion due to its collisions with molecules of air) is typically ten billion times greater than the velocity calculated above. The disturbance of quantum mechanical effects such as particle interference by random thermal motion is why even nano-scale quantum effects are often studied at low temperatures.
A classical question: When does the cricket ball travel its fastest (towards the batsman)?
This question was asked by Dan Trouw of Darwin. Let's answer it using classical mechanics, rather than quantum mechanics, while recognising that quantum mechanics reduces to the classical result in typical macroscopic circumstances, such as cricket.- The force of gravity is easy, it's the weight, W = mg. Let's compare it with the force Fdrag due to turbulent drag. This is given by:where v is the speed, ρ is the density of air, A is the cross-sectional area, and CD is the drag coefficient. This coefficient, which is around unity for very blunt objects and which decreases for streamlined objects, must be measured experimentally, For a sphere it is typically about 0.5. So we have The density of air is about 1.2 kg.m-3. So, for a very fast bowler, with v = 40 m/s, this force is about 2 newtons: for such a bowler, the drag force is about the same as the weight of the cricket ball. For someone bowling at say 20 m/s, the drag force would be only a few tenths of the weight.
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